(2) A student walks 160 m N and then walks 210 m E farther in 140 s . What is the magnitude of the?

(2) A student walks 160 m N and then walks 210 m E farther in 140 s . What is the magnitude of the average velocity of the entire walk? or:(2) A stude

(2) A student walks 160 m N and then walks 210 m E farther in 140 s . What is the magnitude of the average velocity of the entire walk?

or:(2) A student walks 160 m N and then walks 210 m E farther in 140 s . What is the magnitude of the average velocity of the entire walk?

or:The way this question is phrased makes me think it wants the distance covered (as the crow flies) divided by the time. His speed (which is a scalar quantity) is 370m/140s or about 2.6m/s. However it asks for velocity (which is a vector quantity) so we have to work out his actual distance covered from the starting point. If we use 160 and 210 as the adjacent and opposite of a right-angled triangle then do a bit of pythagoras to it, the total distance is the square root of 160\u00b2 + 210\u00b2, which comes to 264m. Therefore his velocity is 264m/140s, which is 1.82m/s (and not the 2.6m/s they were trying to trick you into).

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