Can someone explain how 49c²-112c+64 turns out to be (7c-8)²?

am super confuse or:am super confuseor:it is a perfect square trinomiala\u00b2 - 2ab + b\u00b2 = (a - b)\u00b2a here is 7c, the square of 7c is 49c\u0

am super confuse

or:am super confuse

or:it is a perfect square trinomiala\u00b2 - 2ab + b\u00b2 = (a - b)\u00b2a here is 7c, the square of 7c is 49c\u00b2b here is 8, the square of 8 is 642ab here is 2(7c)(8) = 112c

or:A big part of math is pattern recognition. A lot of homework is just fighting with stuff so you will remember the pattern when you see it again. The most common pattern is (x + a) * (x + b) = x^2 + (a + b)x + ab and the special case (x + a) * (x - a) = x^2 - a^2. When you spot the pattern you can just write the answer from memory.Now study this page until it seems obvious: en.wikipedia.org/wiki/Polynomial_remainder_theorem49c^2 - 112c + 64 = 0 First you notice that 49=7^2. Then you notice that 64=8^2. Then you check to see that 2x7x8=112 so you write the answer from memory: (7c - 8)^2 = 0

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