Cost and Revenue Functions?

The revenue function for a product is R(x)=23x and the cost function for the product is C(x)=x^2+10x+100. The max possible profit that can be made on

The revenue function for a product is R(x)=23x and the cost function for the product is C(x)=x^2+10x+100. The max possible profit that can be made on the product is what amount?

or:The revenue function for a product is R(x)=23x and the cost function for the product is C(x)=x^2+10x+100. The max possible profit that can be made on the product is what amount?

or:you need to max out [32x-(x^2+10x+100)] => max -(x^2-22x+100) = -(X^2-22x+121-11) = -[(x-11)^2-11] = -(x-11)^2+11You will notice that:(x-11)^2 can only be > = zero11 is a positive numberTherefore, you need (x-11)^2 = 0 in order to get the max of 11 => x= 11Now replace X in the initial equation [32x-(x^2+10x+100)] and you will get a result of 21The maximum profit you can get on this product is 21

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