For what values of b does the equation 5x²+bx+12=0 have no real solutions?

I am in algebra II and I am unsure how to solve this! My teacher got -15.49 < b < 15.49 but I have no idea how. Please show me with steps on how to so

I am in algebra II and I am unsure how to solve this! My teacher got -15.49 < b < 15.49 but I have no idea how. Please show me with steps on how to solve, Thanks so much!!

or:I am in algebra II and I am unsure how to solve this! My teacher got -15.49 < b < 15.49 but I have no idea how. Please show me with steps on how to solve, Thanks so much!!

or:Negative b is the place to start,Plus or minus will show you're smart,The radical sits so gent-i-ly,On b square minus 4acNow we're done ... except to say,The whole thing sits on top of 2ax = (-b \u00b1 \u221a(b^2 - 4ac))/2a\"Not real\" means (b^2 - 4ac) is negative. Solve that and you have your answer.

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