Freon-12 has formula CCl2F2. Given a 5.56mg sample of freon-12, what is the number of molecules?

or:Freon-12 has formula CCl2F2. Given a 5.56mg sample of freon-12, what is the number of molecules?or:Ok so you take .00556g*(1mol/120.898)*(6.022x10

or:Freon-12 has formula CCl2F2. Given a 5.56mg sample of freon-12, what is the number of molecules?

or:Ok so you take .00556g*(1mol/120.898)*(6.022x10^23molecules/mol)=2.819x10^19 molecules.

or:This is simple arithmetic if you have a periodic table. You do have a printed periodic table, right? You can get the information at www.chemicalelements.com/index.html but you really need your own printed copy to carry with you. It will be a primary reference for everything you do. There is a diagonal line, B-C, Si-P, Ge-As, Sb-Te, and Po-At. Elements to the left of the line are metals, meaning they lose an electron easily, elements to the right of the line are non-metals, and elements on the line are semiconductors.C - 12.011Cl2 - 2 x 35.4527 = 70.9054F2 - 2 x 18.9984032 = 37.9968064--------------------------- ADD120.913 We can drop the rest because the figure for carbon only has three decimals. This is the mass in grams of 6.023 x 10^23 molecules of the given substance.(5.56 x 10^-3 g)/120.913g x 6.023 x 10^23 = 2.769584743 x 10^19 molcules

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