Grade 6 Math-Percentage homework help.... Thank you?
If 25% of the boys left the computer club, the ratio of the number of boys who remained to the number of girls would be 5:8. On Childrens Day celebrat
If 25% of the boys left the computer club, the ratio of the number of boys who remained to the number of girls would be 5:8.
On Children's Day celebration, each girl received 4 sweets fewer than each boy. The received 294 more sweets than the girls and a total of 1806 sweets were given out.
(a)What was the ratio of the number of boys to the number of girls in the computer club? Give your answer in the simplest form?
(b) What was the total number of boys and girls in the club?
or:If 25% of the boys left the computer club, the ratio of the number of boys who remained to the number of girls would be 5:8. On Children's Day celebration, each girl received 4 sweets fewer than each boy. The received 294 more sweets than the girls and a total of 1806 sweets were given out.(a)What was the ratio of the number of boys to the number of girls in the computer club? Give your answer in the simplest form?(b) What was the total number of boys and girls in the club?
or:Total # of candies was 1806, boys got 294 more so 1806/2=903, 903-294=609, or the # the girls got, and 903+ that extra 294=1197,or the #the boys got... Obviously there's fewer boys here, because dividing the sweets evenly the girls got less each because of there being more of them... So find the largest # that can go into 1197 evenly, subtract 4, should be the max # that goes into 609 evenly, which should be the number of boys and girls... If I'm wrong then there's just a flaw in the math somewhere but you should be able to figure it out now...
or:This is not grade school math, this is high school algebra.
or:Letx = the number of girlsy = the number of boys If 25% of the boys left the computer club, the ratio of the number of boys who remained to the number of girls would be 5:8.(a)What was the ratio of the number of boys to the number of girls in the computer club?25% = 25/100 = 1/4So, if 1/4 of the boys left, there would remain 3/4. In mathematical terms the ratio would then be:(3/4)y / x = 5/8.But as actually nobody has left, the ratio is:y / x = (5/8) / (3/4) = 5/6.___________________[...] each girl received 4 sweets fewer than each boy. They received 294 more sweets than the girls and a total of 1806 sweets were given out.And the ultimate question is:(b) What was the total number of boys and girls in the club?We'll firstly have to figure out how those sweets were distributed. And we introduce another unknown:n = number of sweets for each girl.xn = number of sweets for the girls (in total). And y(n + 4) = sweets for the boys, as each boy gets 4 sweets more than each girl.The ratio y:x = 5:6 is now very useful, because it follows immediately:y = (5/6)x, andx = (6/5)y, which comes in handy for substitution purposes.Now we can build our system of two linear equations:(Note that I have rephrased the 1st condition to: \"Each boy gets 4 sweets more than each girl\". If you want to do it according to the original text, n would then represent the number of sweets for each boy, and the number of sweets for the subset of girls would then equal x(n - 4).)(1) y(n + 4) + nx = 1806The boys received 294 more sweets than the girls, which is just the difference:(2) y(n + 4) - nx = 294Resolve parentheses and substitute (6/5)y for x(1.1) ny + 4y + (6/5)ny = 1806(2.1) ny + 4y - (6/5)ny = 294(1.2) (11/5)ny + 4y = 1806(2.2) -(1/5)ny + 4y = 294 ;; Times 11(2.3) -(11/5)ny + 44y = 3234Add equations (1.2) + (2.3)48y = 5040y = 105.There are 105 boys in the club.As x=(6/5)y, x = 126.There are 126 girls in the club.x + y = 231.The total number of boys and girls in the club is 231.Btw, each girl gets 6 sweets, and each boy gets 10.
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