H2+CO=CH3OH?
68.5g of CO is reacted with 8.60g H2,which is the limited reactant, what mass in grams of methanol is produced, and of 50.1g is produced what is the p
68.5g of CO is reacted with 8.60g H2,which is the limited reactant, what mass in grams of methanol is produced, and of 50.1g is produced what is the percentage yield?
or:68.5g of CO is reacted with 8.60g H2,which is the limited reactant, what mass in grams of methanol is produced, and of 50.1g is produced what is the percentage yield?
or:First you get your numbers right. The product has four hydrogens, so you need four in the reactants.2H2 + CO = CH3OH Add spaces so you can see clearly what you have.Now you look at that and see that one mole of H2 gives one mole of CH3OH. You do have a printed periodic table, right? You can get the information at www.chemicalelements.com/index.html but you really need your own printed copy to carry with you. It will be a primary reference for everything you do. Hydrogen atomic mass is 1.00794 so a mole of H2 is 2.01588 grams. You are given 8.6/2.01588 = 4.266126952 moles.Now you get your periodic table and add up the molar mass of CH3OH and multiply that by 4.266126952 and that is your product. I don't understand the rest of your question.
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