How do you expand and simplify (9x-1)(x-4) - (3x+1)(3x-1)?

For my math project or:For my math projector:(9x-1)(x-4)-(3x+1)(3x-1)= 9x.x - 9x.4 - 1.x + 4.1 - 9x.x +1= 9x.x - 36x - x +4 - 9x.x +1= -37.x + 5or:Thi

For my math project

or:For my math project

or:(9x-1)(x-4)-(3x+1)(3x-1)= 9x.x - 9x.4 - 1.x + 4.1 - 9x.x +1= 9x.x - 36x - x +4 - 9x.x +1= -37.x + 5

or:This does not require \"expand\" or \"simplify, it requires \"evaluate\".(9x - 1)(x - 4) - (3x + 1)(3x - 1) Add spaces to improve readability. (9x - 1)(x - 4) Multiply each term in the first parentheses by each term in the second.9x^2 - 36x - x + 4

or:Let's expand the two products of sums:(9x - 1) (x - 4) = 9x^2 - 36x - x + 4 ;; and simplify it9x^2 - 37x + 4.Now we do the same with the other one. (Note that (a + b) (a - b) reduces to a^2 - b^2, because the linear terms -ab + ab cancel out):(3x + 1) (3x - 1) = 9x^2 - 1.Now we subtract the two terms(9x^2 - 37x + 4) - (9x^2 - 1) ;; Solve the parentheses. The minus-sign in front of the second term is just a shorthand for a factor of -1.(9x^2 - 37x + 4) + (-1) (9x^2 - 1)9x^2 - 37x + 4 - 9x^2 + 1 ;; Again, simplify-37x + 5.

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