How do you solve this comparison?

√(〖2,7〗^2-x^2 )= √([√((2,5-x)^2+(√(〖2,7〗^2-x^2 ))^2 )]^2 -(2,5-x)^2 )I have to solve this comparison for school, but I cant

√(〖2,7〗^2-x^2 )= √([√((2,5-x)^2+(√(〖2,7〗^2-x^2 ))^2 )]^2 -(2,5-x)^2 )

I have to solve this comparison for school, but I can't solve it.... so, I would really appreciate it if you just tried to solve it and give me the answer if you solved it.

Thanks

or:\u221a(\u30162,7\u3017^2-x^2 )= \u221a([\u221a((2,5-x)^2+(\u221a(\u30162,7\u3017^2-x^2 ))^2 )]^2 -(2,5-x)^2 )I have to solve this comparison for school, but I can't solve it.... so, I would really appreciate it if you just tried to solve it and give me the answer if you solved it.Thanks

or:use a calculator

Tags:mathematics,