I have 10 and 7 and I take out 2 what is the probability percentage of me taking out 2 different?

if I have 10 dark chocolates and 7 milk chocolates and I take out 2 chocolates what is the probability percentage of me taking out 2 different types o

if I have 10 dark chocolates and 7 milk chocolates and I take out 2 chocolates what is the probability percentage of me taking out 2 different types of chocolates

or:if I have 10 dark chocolates and 7 milk chocolates and I take out 2 chocolates what is the probability percentage of me taking out 2 different types of chocolates

or:Split it to two independent scenarios, then add up their probabilities:1) Dark is picked, followed by white.2) White is picked, followed by dark.Assuming uniform distribution of the selection (would not recommend when involving chocolate!), and that the piece is removed permanently,P = (10 / 17) * (7 / 16) + (7 / 17) * (10 / 16) ~ 51.471%.Now, test in an environment you can count - 2 dark, 1 milk (or preferably 3 and 2), and name them 1, 2, 3.P = 2 / 3Actual scenarios are: 12 (bad), 13, 21 (bad), 23, 31, 32 - total of 4 / 6, matching the above.

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