If a:b=2:3 and b:c=5:6 find the ratios a:b:c?

or:If a:b=2:3 and b:c=5:6 find the ratios a:b:c?or:a:b=2:3 means for every 2 'a's there are 3 'b's, so for 1 'a' there will be 1.5 'b'a:b can be wri

or:If a:b=2:3 and b:c=5:6 find the ratios a:b:c?

or:a:b=2:3 means for every 2 'a's there are 3 'b's, so for 1 'a' there will be 1.5 'b'a:b can be written as 1:1.5and similarly, for 5 'b's there are 6 'c's so for 1 'b' there will be 6/5 'c' and for 1.5 'b' there will be (1.5x6/5)=9/5 'c'a:b:c = 1:1.5:9/5 ..................answer!

or:Imagine three intermeshed cogwheels a, b, c.a:b=2:3 and b:c=5:6 , which translates to:IF wheel a turns twice, THEN wheel b will turn 3 times, ANDIF wheel b turns 5 times, THEN wheel c will turn 6 times.It would be nice, if b=b, but clearly 3\u22605. To get this fixed we scale the fractions.p/p = p^1 * p^-1 = p^0 = 1 ; p \u2260 0.a/b = 2/3 * 5/5 = 10/15b/c = 5/6 * 3/3 = 15/18And there you are:a : b : c = 10 : 15 : 18 ; integers onlyor a : b : c = 1 : 1.5 : 1.8 ; decimalsora : b : c = 1 : 3/2 : 9/5 ; fractionsbut I don't favour the hybrid representation ;)

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