Sequence maths question?
The first four terms of a sequence areT1 = 12 T2 = 12 + 22 T3 = 12 + 22 + 32 T4 = 12 + 22 + 32 + 42.(a) The nth term is given by Tn =1/6n(n + 1)(2n +
The first four terms of a sequence are
T1 = 12 T2 = 12 + 22 T3 = 12 + 22 + 32 T4 = 12 + 22 + 32 + 42.
(a) The nth term is given by Tn =1/6n(n + 1)(2n + 1).
(b) A new sequence is formed as follows.
U1 = T2 – T1 U2 = T3 – T2 U3 = T4 – T3
Q. Write down a formula for the nth term, Un
or:The first four terms of a sequence areT1 = 12 T2 = 12 + 22 T3 = 12 + 22 + 32 T4 = 12 + 22 + 32 + 42.(a) The nth term is given by Tn =1/6n(n + 1)(2n + 1).(b) A new sequence is formed as follows.U1 = T2 \u2013 T1 U2 = T3 \u2013 T2 U3 = T4 \u2013 T3Q. Write down a formula for the nth term, Un
or:Tn =1/6n(n + 1)(2n + 1)Tn =(1/(6n))(n + 1)(2n + 1)Tn =(1/6)n(n + 1)(2n + 1)Tn =(1/(6n))(n + 1)(2n + 1)Tn =1/6n(n + 1)(2n + 1)Any of these is a possible interpretation of your statement. We are not supposed to have to guess at your meaning.
